If $$l + m + n = 9$$ and $$l^2 + m^2 + n^2 = 31$$, then the value of lm + mn + nl will be
Given : $$l + m + n = 9$$
Squaring both sides, we get :
=>Â $$(l + m + n)^2 = (9)^2$$
=> $$(l^2+m^2+n^2)+2(lm+mn+nl)=81$$
=> $$31+2(lm+mn+nl)=81$$
=> $$2(lm+mn+nl)=81-31=50$$
=> $$lm+mn+nl=\frac{50}{2}=25$$
=> Ans - (C)
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