A thief is stopped by a policeman from a distance of 350 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 5 km/h and that of the policeman as 7 km/h, how far the thief would have run, before he is over-taken?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 5 km/hr and speed of policeman = 7 km/hr

=> Relative speed = 7 - 5 = 2 km/hr

Distance between them = 350 metres = 0.35 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.35}{2} = \frac{7}{40}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$5 \times \frac{7}{40}$$

= 0.875 km = 875 metres

=> Ans - (A)