Question 30

Triangle PQR is inscribed in a circle such that P, Q and R lie on the circumference. If PQ is the diameter of the circle and $$\angle PQR = 40$$°, then what is the value (in degrees) of $$\angle QPR$$?

Solution

As PQ is the diameter of the triangle, angle PRQ is 90°.

So, angle PRQ+angle PQR+angle RPQ=180°.

So,angle QPR=180°-40°-90°=50°.

C is correct choice.

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