Question 30

Starting from his house one day, a student walks at a speed of $$2\frac{1\ }{2}$$ kmph and reaches his school 6 minutes late. Next day he increases his speed by 1 kmph and reaches his school 6 minutes early. How far is the school from the house?

Solution

Assume the distance to be $$x$$ km.

When he travels at the speed of 2.5 km/hr he is 6 minutes late.

When he travels at the speed of 3.5 km/hr he is 6 minutes early

$$\frac{\ x}{2.5}$$ - $$\frac{\ x}{3.5}$$ = $$\frac{\ 12}{60}$$

$$\frac{\ 2x}{5}-\frac{\ 2x}{7}\ =\frac{\ 1}{5}$$

$$\frac{\ 4x}{35}=\frac{\ 1}{5}$$

$$\ x=\frac{\ 7}{4}=\ 1\frac{\ 3}{4}$$ km

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

SNAP Quant Questions | SNAP Quantitative Ability

SNAP Logical Reasoning Questions SNAP Data Interpretation Questions

SNAP Syllabus

SNAP Admit Card

SNAP Cutoffs

SNAP Eligibility Criteria

SNAP Exam Dates

SNAP Colleges List

SNAP Study Material

SNAP Registration

SNAP Result

SNAP Previous Year Papers

SNAP Crash Course

SNAP Mock Tests