Solution
Given : $$z+\frac{2}{z}=2$$
=> $$\frac{z^2+2}{z}=2$$
=> $$z^2=2z-2$$ -----------(i)
To find : $$(2-2z+z^{2})(2+2z-z^{2})$$
Substituting value from equation (i), we get :
= $$[2-2z+(2z-2)][2+2z-(2z-2)]$$
= $$(0)\times(0)=0$$
=> Ans - (A)
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