How many solutions does a pair of linear equations will have, if the equations are 4x+5y-6=0 and 16x+20y+20=0?
Equations : $$4x+5y-6=0$$ and $$16x+20y+20=0$$
The ratio of coefficients is = $$\frac{4}{16}$$ $$,\frac{5}{20}$$ $$,\frac{-6}{20}$$
=> $$\frac{1}{4}=\frac{1}{4}\neq\frac{-3}{10}$$
$$\because\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq\frac{c_1}{c_2}$$, thus the equations have no solutions.
=> Ans - (A)
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