If the area of a square is 48, then what is the diagonal of the square?
Let side of square = $$s$$ units and diagonal = $$d$$ units
=> Area = $$s^2=48$$
Also, $$d=\sqrt{s^2+s^2}=\sqrt{2s^2}$$
=> $$d=\sqrt{2\times48}=\sqrt{96}$$
=> $$d=4\sqrt{6}$$
=> Ans - (A)
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