What is the length of the longest rod that can be placed in a room which is 3 metres long, 4 metres broad and 5 metres high?
Length = $$l=3$$ m, Breadth = $$b=4$$ m and Height = $$h=5$$ m
Length (in metres) of the longest rod that can be placed in the room is its diagonals.
=> Diagonal =Â $$d=\sqrt{l^2+b^2+h^2}$$
=> $$d=\sqrt{(3)^2+(4)^2+(5)^2}$$
=> $$d=\sqrt{9+16+25}=\sqrt{50}$$
=> $$d=5\sqrt{2}$$ m
=> Ans - (C)
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