Question 28

If 11 # 2 @ 6 = 78 and 15 # 4 @ 8 = 152, then 17 # 6 @ 7 = ?

Solution

Given : 11 # 2 @ 6 = 78 and 15 # 4 @ 8 = 152

If we replace # by '+' and @ by 'x', and perform the add operation first, we get the desired result.

Eg :- $$(11+2)\times6=78$$

and $$(15+4)\times8=152$$

Similarly, $$(17+6)\times7=161$$

=> Ans - (A)

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