Find the value of $$\dfrac{1}{1 + \dfrac{1}{3-\dfrac{4}{2+\dfrac{1}{3-\dfrac{1}{2}}}}}$$ + $$\dfrac{3}{3 - \dfrac{4}{3+\dfrac{1}{2-\dfrac{1}{2}}}}$$

$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{1}{3-\frac{1}{2}}}}}$$

=$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{1}{\frac{5}{2}}}}}$$

=$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{2}{5}}}}$$

=$$\frac{1}{1 + \frac{1}{3-\frac{20}{12}}}$$

=$$\frac{1}{1 + \frac{1}{3-\frac{20}{12}}}$$

=$$\frac{1}{1 + \frac{12}{16}}$$

=$$\frac{1}{\frac{28}{16}}$$

=$$\frac{16}{28}$$

Similarly, Second term can be reduced to $$\frac{33}{21}$$ or $$\frac{11}{7}$$

Sum will be = $$\frac{11}{7}$$ + $$\frac{4}{7}$$ = $$\frac{15}{7}$$