Find the value of $$\dfrac{1}{1 + \dfrac{1}{3-\dfrac{4}{2+\dfrac{1}{3-\dfrac{1}{2}}}}}$$ + $$\dfrac{3}{3 - \dfrac{4}{3+\dfrac{1}{2-\dfrac{1}{2}}}}$$
$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{1}{3-\frac{1}{2}}}}}$$
=$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{1}{\frac{5}{2}}}}}$$
=$$\frac{1}{1 + \frac{1}{3-\frac{4}{2+\frac{2}{5}}}}$$
=$$\frac{1}{1 + \frac{1}{3-\frac{20}{12}}}$$
=$$\frac{1}{1 + \frac{1}{3-\frac{20}{12}}}$$
=$$\frac{1}{1 + \frac{12}{16}}$$
=$$\frac{1}{\frac{28}{16}}$$
=$$\frac{16}{28}$$
Similarly, Second term can be reduced to $$\frac{33}{21}$$ or $$\frac{11}{7}$$
Sum will be = $$\frac{11}{7}$$ + $$\frac{4}{7}$$ = $$\frac{15}{7}$$
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