1, 4, 15, 64, 325, 1955

Solution

4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6

The nth term is of the form,

$$T_n=(T_{n-1}\times n)+n$$

The last term does not follow the pattern and is thus the wrong number in the sequence.

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