Question 25

∆PQR is right angled at Q. If $$cot P = \frac{5}{12}$$, then what is the value of $$tan R$$ ?

Solution

Given : $$cot P = \frac{5}{12}$$

=> $$cot P = \frac{PQ}{QR}=\frac{5}{12}$$ -----------(i)

Now, $$tan R=\frac{PQ}{QR}$$

Substituting value form equation (i), we get :

=> $$tan R=\frac{5}{12}$$

=> Ans - (B)

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