Question 25
∆PQR is right angled at Q. If $$cot P = \frac{5}{12}$$, then what is the value of $$tan R$$ ?
Solution
Given : $$cot P = \frac{5}{12}$$
=> $$cot P = \frac{PQ}{QR}=\frac{5}{12}$$ -----------(i)
Now, $$tan R=\frac{PQ}{QR}$$
Substituting value form equation (i), we get :
=> $$tan R=\frac{5}{12}$$
=> Ans - (B)
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