Instructions

The table give below shows the marks obtained by six students in 5 different subjects.

Question 25

Marks obtained by student B is how much percent more than the marks obtained by A?

Solution

Total marks obtained by student A

= 72 + 75 + 80 + 82 + 93 = 402

Total marks obtained by student B

= 87 + 94 + 78 + 87 + 95 = 441

=> Required % = $$\frac{(441-402)}{402}\times100$$

$$\approx\frac{39}{4}=9.7\%$$

=> Ans - (C)

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