Instructions
The table give below shows the marks obtained by six students in 5 different subjects.
Question 25
Marks obtained by student B is how much percent more than the marks obtained by A?
Solution
Total marks obtained by student A
= 72 + 75 + 80 + 82 + 93 = 402
Total marks obtained by student B
= 87 + 94 + 78 + 87 + 95 = 441
=> Required % = $$\frac{(441-402)}{402}\times100$$
$$\approx\frac{39}{4}=9.7\%$$
=> Ans - (C)
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