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Question 25

Let S be a set of positive integers such that every element n of S satisfies the conditions

A. 1000 <= n <= 1200

B. every digit in n is odd

Then how many elements of S are divisible by 3?

Solution
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The no. has all the digits as odd no. and is divisible by 3. So the possibilities are 

1113
1119
1131
1137
1155
1173
1179
1191
1197
Hence 9 possibilities . 

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