Question 25
In ∆ABC measure of angle B is $$90^0$$. If cot A = 8/15, and AB = 0.8cm, then what is the length (in cm) of side BC?
Solution
Given : AB = 0.8 cm and cot A = 8/15
To find : BC = ?
Solution : In right $$\triangle$$ ABC,
=> $$cot(A)=\frac{AB}{BC}$$
=> $$\frac{8}{15}=\frac{0.8}{BC}$$
=> $$BC=\frac{15}{8}\times0.8=1.5$$ cm
=> Ans - (C)
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