Question 25

In ∆ABC measure of angle B is $$90^0$$. If cot A = 8/15, and AB = 0.8cm, then what is the length (in cm) of side BC?

Solution

Given : AB = 0.8 cm and cot A = 8/15

To find : BC = ?

Solution : In right $$\triangle$$ ABC,

=> $$cot(A)=\frac{AB}{BC}$$

=> $$\frac{8}{15}=\frac{0.8}{BC}$$

=> $$BC=\frac{15}{8}\times0.8=1.5$$ cm

=> Ans - (C)

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