Question 24

∆PQR is right angled at Q. If m$$\angle$$R = $$30^\circ$$, then find the value of $$(\cos P - \frac{1}{3})$$.

Solution

Sum of angles of $$\triangle$$ PQR = $$\angle P+\angle Q+\angle R=180^\circ$$

=> $$\angle P+90^\circ+30^\circ=180^\circ$$

=> $$\angle P=180^\circ-120^\circ=60^\circ$$

To find : $$(\cos P - \frac{1}{3})$$

= $$cos(60^\circ)-\frac{1}{3}$$

= $$\frac{1}{2}-\frac{1}{3}$$

= $$\frac{1}{6}$$

=> Ans - (A)

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