Question 21

The area of an equilateral triangle is $$49\sqrt3 cm^2$$. Find its side (in cm).

Solution

Let side of equilateral triangle = $$s$$ cm

Area of equilateral triangle = $$\frac{\sqrt3}{4} (s)^2=49\sqrt3$$

=> $$s^2=49\times4$$

=> $$s=\sqrt{7\times7\times2\times2}$$

=> $$s=7\times2=14$$ cm

=> Ans - (B)

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