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The area of a square is $$40.5 cm^{2}$$. Find the length of its diagonal (in cm).
Let side of square = $$s$$ cm and its diagonal = $$d$$ cm
Area = $$s^2=40.5$$
Now, $$d^2=s^2+s^2$$
=> $$d^2=40.5+40.5=81$$
=> $$d=\sqrt{81}=9$$ cm
=> Ans - (A)
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