CAT 2006 Question Paper Question 21

Question 21

A semi-circle is drawn with AB as its diameter. From C, a point on AB, a line perpendicular to AB is drawn meeting the circumference of the semi-circle at D. Given that AC = 2 cm and CD = 6 cm, the area of the semi-circle (in sq. cm) will be:

Solution

In triangle CDO, which is a right anged triangle, we can use pythagoras theorem.

$$6^2$$ + $$(r-2)^2$$ = $$r^2$$

=> 36 + $$r^2 - 4r + 4$$ = $$r^2$$

=> 4r = 40

=> r = 10

=> Area = $$\pi *10*10/2$$ = $$50\pi $$

Create a FREE account and get:

All Quant CAT Formulas and shortcuts PDF
30+ CAT previous papers with solutions PDF
Top 500 CAT Solved Questions for Free

Comments

Register with

OR

CAT DILR Questions | LRDI Questions For CAT

CAT Data Interpretation

CAT DI Data Change Over Period

CAT Tables With Missing Values

CAT DI Venn Diagrams

CAT DI Special Charts

CAT DI Maxima & Minima

CAT Quant-Based DI

CAT DI Connected Sets

CAT DI Miscellaneous

CAT LR Arrangement

CAT LR Selections With Conditions

CAT LR Coins & Weights

CAT LR Truth & Lie

CAT LR Scheduling

CAT LR Games & Tournaments

CAT 2D & 3-D LR

CAT Quant-Based LR

CAT LR Miscellaneous

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Reading Comprehension (RC)

CAT Para Jumbles

CAT Para Completion and Summary Questions

CAT Grammar & Sentence Correction

CAT Critical Reasoning

Boost your Prep!

Download App