If $$\frac{2x+3y}{3x-4y}=\frac{11}{7}$$, then the value of $$\frac{x}{y}$$ is _______
Expression : $$\frac{2x+3y}{3x-4y}=\frac{11}{7}$$
=> $$7(2x+3y)=11(3x-4y)$$
=> $$14x+21y=33x-44y$$
=> $$33x-14x=21y+44y$$
=> $$19x=65y$$
=> $$\frac{x}{y}=\frac{65}{19}$$
=> Ans - (A)
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