Solution
Since, $$1<x<2$$
$$\sqrt{\left(2x-5\right)^2}=5-2x$$ (as value in square root should be positive)
$$=$$> $$\sqrt{\left(2x-5\right)^2}+2\sqrt{\left(x-1\right)^2}=5-2x+2\left(x-1\right)=5-2x+2x-2=3$$
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