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If $$\sigma_ {s}$$ is the stress in bar and $$\tau_{bd}$$ is the design bond stress, then the development length of a bar of diameter \phi is given by
$$\frac{4 \phi \sigma_ {s} }{\tau_{bd}}$$
$$\frac{ \phi \sigma_ {s} }{4\tau_{bd}}$$
$$\frac{2 \phi \sigma_ {s} }{3\tau_{bd}}$$
$$\frac{\phi \sigma_ {s} }{3\tau_{bd}}$$
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