SSC CGL Tier 1 9 August 2015 Shift 2

Question 180

If $$\frac{x}{y}$$=$$\frac{3}{4}$$ the ratio of $$(2x+3y)$$ and $$(3y-2x)$$ is

Solution

Let $$x = 3k$$ and $$y = 4k$$

=> $$\frac{2x + 3y}{3y - 2x}$$

= $$\frac{6k + 12k}{12k - 6k}$$

= $$\frac{18}{6}$$

= $$\frac{3}{1}$$ = 3 : 1

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