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Question 174
If $$x= p$$ $$cosec θ$$ and $$y= q$$ $$cot θ$$, then the value of $$\frac{x^2}{p^2}-\frac{y^2}{q^2}$$ is
Solution
$$x= p$$ $$cosec θ$$
=> $$cosec\theta$$ = $$\frac{x}{p}$$
Also, $$y= q$$ $$cot θ$$
=> $$cot\theta$$ = $$\frac{y}{q}$$
$$\because$$ $$cosec^2\theta-cot^2\theta$$ = 1
=> $$\frac{x^2}{p^2}$$ - $$\frac{y^2}{q^2}$$ = 1
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