One pipe can fill a tank three times as fast as another pipe. If the two pipes together can fill the tank in 36 minutes, then the slower pipe will take how much time to fill the tank alone?
Solution
Let slower pipe fill the tank at the rate x units/ minute.
Faster pipe will fill tank at the rate of 3x units/ minute
Number of units filled by both the pipes in a minute = 4x
Total time taken to fill tank = 36 minutes
capacity of tank = 36$$\times\ $$4x = 144x
Time taken by slower pipe to fill the tank = $$\frac{144x}{x}$$ = 144 minutes
Answer is option D.
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