X is four years older than Y who is twice as old as Z. If the total ages of X, Y and Z be 34, how old is X?
Let Z's age = $$m$$ years
=> Y's age = $$2m$$ years
and X's age = $$(2m+4)$$ years
Sum of ages of X,Y and Z = $$(2m+4)+2m+m=34$$
=> $$5m+4=34$$
=> $$5m=34-4=30$$
=> $$m=\frac{30}{5}=6$$
$$\therefore$$ X's age = $$2(6)+4=16$$ years
=> Ans - (D)
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