Question 169

X is four years older than Y who is twice as old as Z. If the total ages of X, Y and Z be 34, how old is X?

Solution

Let Z's age = $$m$$ years

=> Y's age = $$2m$$ years

and X's age = $$(2m+4)$$ years

Sum of ages of X,Y and Z = $$(2m+4)+2m+m=34$$

=> $$5m+4=34$$

=> $$5m=34-4=30$$

=> $$m=\frac{30}{5}=6$$

$$\therefore$$ X's age = $$2(6)+4=16$$ years

=> Ans - (D)

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