Question 16

The average age of three men is 50 years and their ages are in the proportion 3:5:7. The age of the youngest man is:

Solution

Given the proportion of ages of three men are 3:5:7.

Let their ages be 3k, 5k, 7k ,where k is any constant.

Given average of ages of three men = 50

$$\Rightarrow \frac{3k+5k+7k}{3} = 50$$

$$\Rightarrow \frac{15k}{3} = 50$$

$$\Rightarrow 5k = 50$$

$$\Rightarrow k = 10$$

Therefore the ages of three men are 30, 50, and 70 years.

The age of the youngest men is 30 years.

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