Question 16

A train is moving at the speed of 90 km/hr. How many seconds it will take to cover a distance of 2275 meter?

Solution

Speed of train = 90 km/hr = $$(90\times\frac{5}{18})=25$$ m/s

Time taken to cover 2275 m = distance/speed

= $$\frac{2275}{25}=91$$ seconds

=> Ans - (B)

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