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Question 16
A train is moving at the speed of 90 km/hr. How many seconds it will take to cover a distance of 2275 meter?
Solution
Speed of train = 90 km/hr = $$(90\times\frac{5}{18})=25$$ m/s
Time taken to cover 2275 m = distance/speed
= $$\frac{2275}{25}=91$$ seconds
=> Ans - (B)
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