S, T and U together can complete a work in 30 days. If the ratio of efficiency of S, T and U is 20: 15: 12 respectively, then in how many days U alone can complete the same work?
Let efficiencies of S, T and U be $$20x,15x$$ and $$12x$$ units/day respectively.
S, T and U together can complete the work in 30 days
=> Total work to be done = $$30\times(20x+15x+12x)=1410x$$ units
$$\therefore$$ Time taken by U alone to complete the work = $$\frac{1410x}{12x}=\frac{235}{2}$$ days
=> Ans - (B)
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