We know that $$\sqrt3=1.7$$ and $$\sqrt4=2$$.
$$\sqrt2=1.4$$ and $$\sqrt8=2.8$$
I) $$4\sqrt3=4\times1.7\approx6.8$$
and $$3\sqrt4=3\times2=6$$
=> $$4\sqrt3>3\sqrt4$$
II) $$8\sqrt2=8\times1.4\approx12$$
and $$2\sqrt8=2\times2.8=5.6$$
=> $$8\sqrt2>2\sqrt8$$
$$\therefore$$ Both I and II are true.
=> Ans - (D)
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