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85 litres of a mixture contain milk and water in the ratio 27:7. How much more water is required to be added in the mixture, so that the resulting mixture contains milk and water in the ratio 3:1?
Quantity of milk in the mixture = $$\frac{27}{27+7}\times\ 85\ =\ 67.5$$.
Let us assume that X litres of water is added which makes the quantity of new solution = 85+X.
Milk content remains the same which means that:
$$\frac{3}{3+1}\times\ \times\ \left(85+X\right)=67.5$$.
This gives X = 5 litres.
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