If 12 (20) 16 and 21 (35) 28, then what is value of A in 48 (80) A ?
The numbers are of the form : $$3x(5x)4x$$, where $$x$$ is the L.C.M. of the three terms
Eg = 12 (20) 16, L.C.M. = 4 and it can be represented as = $$3(4),5(4),4(4)$$
Similarly, for 21 (35) 28 L.C.M. = 7
Thus, for 48 (80) A, L.C.M. = 16
=> $$A=16\times4=64$$
=> Ans - (C)
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