Question 147

$$7-(4\times3-(-10)\times8\div(-4))$$ is equal to:

Solution

$$7-(4\times3-(-10)\times8\div(-4))$$

Using BODMAS

$$=7-(4\times 3-(-10)\times (-2))$$

$$=7-(12-20)$$

$$=7+8$$

$$=15.$$

D is correct choice.

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