Question 145

A man bought some eggs of which 10% are rotten. He gives 80% of the remainder of his reighbours. Now he is left out with 36 eggs. How many eggs he bought?

Solution

Let the man bought $$100x$$ eggs

Eggs left after removing the rotten ones = $$100x-(\frac{10}{100}\times100x)=90x$$

Eggs given to neighbours = $$\frac{80}{100}\times90x=72x$$

Thus, eggs remaining = $$90x-72x=36$$

=> $$18x=36$$

=> $$x=\frac{36}{18}=2$$

$$\therefore$$ Number of eggs bought = $$2\times100=200$$

=> Ans - (D)

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