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If $$\tan\theta=\frac{\sin\alpha-\cos\alpha}{\sin\alpha+\cos\alpha}$$ then $$\sin\alpha+\alpha$$ is
$$\pm\sqrt{2}\sin\theta$$
$$\pm\sqrt{2}\cos\theta$$
$$\pm\frac{1}{\sqrt{2}}\sin\theta$$
$$\pm\frac{1}{\sqrt{2}}\cos\theta$$
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