Question 14

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In triangles $$ABC$$ and $$ADC$$ in the above figure, $$\angle BAC = \angle ADC = 90^\circ$$. Also, $$DC$$ is $$2$$ units long and $$AC$$ is $$4$$ units long. What is the length of $$BC$$?

Solution

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Triangle CDA will be similar to Triangle CAB with AAA similarity.
This gives : $$\frac{CD}{CA}=\frac{CA}{CB}$$
==> $$\frac{2}{4}=\frac{4}{BC}$$
==>BC = 8 units i.e. Option A.

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