Question 138
If 0 is the circumcentre of triangle ABC and OD ⊥ BC, then ∠BOD must be equal to
Solution
O is the circumcentre of the triangle ABC
=> $$\angle$$BOC = 2$$\angle$$BAC
Also, $$\angle$$BOD = $$\frac{1}{2} \angle$$BOC
$$\therefore$$ $$\angle$$BOD = $$\angle$$BAC
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