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Let $$A = \left\{x \epsilon R/x^2 < 9\right\}$$ and $$B = \left\{x \epsilon R/4 < x^2 < 16\right\}$$ then $$A \cap B =$$
$$(-3, -2) \cup (2, 3)$$
$$\phi$$
(2, 3)
(-3, -2)
A/q
A = (-3,3)
B = (-4,-2) U (2,4)
So $$A \cap B = $$Â (-3,-2) U (2,3) Answer
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