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If A, B are two sets such that $$n(A - B) = 40, n(B - A) = 57$$ and $$n(A \cap B) = 16$$ then n(A) =
Solution
n(A)=n(A-B)+n(A∩B)
=40+16
=56
Therefore, n(A) is 56.
Now n(B)=n(A∩B)+n(B-A)
Therefore, n(B) is 16+57 = 73.
n(B)=73.
Hence n(B)=73 Answer
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