Question 136

If P is the circum-center in ΔABC, ∠BPC = 130°, then what is the value (in degrees) of ∠BAC?

Solution

Given : P is the circum-center in ΔABC and ∠BPC = 30°

To find : $$\angle$$ BAC = ?

Solution : In a circle, angle subtended by an arc at the centre is double the angle subtended by the same arc on any other point on the circle

=> $$\angle BPC = 2 \times \angle BAC$$

=> $$\angle$$ BAC = $$\frac{130^\circ}{2}=65^\circ$$

=> Ans - (C)

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