Out of 4 numbers, whose average is 60, the first one is onefourth of the sum of the last three. The first number is
let the four numbers be a,b,c,d
average = $$\frac{sum}{number of elements}$$
it is given that a = (b+c+d)/4
average = 60
60 = $$\frac{5a}{4}$$
a = 48
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