Question 131
A number between 1000 and 2000 which when divided by 30, 36 & 80 gives a remainder 11 in each case is
Solution
LCM of given 3 numbers (30, 36, 80) = 720
Multiple of 720 between 1000 and 2000 is 1440.
$$\therefore$$ Number which gives a remainder 11 in each case (1440 + 11) = 1451
Hence, option A is the correct answer.
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