Question 13

The inradius of triangle is 4 cm and its area is 34 sq. cm. the perimeter of the traingle is

Solution

Area of triangle = in-radius $$\times$$ semi-perimeter

In radius = 4 cm

Let perimeter of triangle = $$x$$ cm

=> Semi-perimeter = $$\frac{x}{2}$$ cm

=> Area = $$4 \times \frac{x}{2}=34$$

=> $$2x=34$$

=> $$x=\frac{34}{2}=17$$ cm

=> Ans - (B)

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