Question 12

If 'O' is the incentre of the Δ PQR. If ∠POR = 115°,then value of ∠PQR is

Solution

Given : O is the incentre of $$\triangle$$ PQR and $$\angle$$ POR = 115°

To find : $$\angle$$ PQR = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{\theta}{2}$$

=> $$115^\circ=90^\circ+\frac{\theta}{2}$$

=> $$\frac{\theta}{2}=115^\circ-90^\circ=25^\circ$$

=> $$\theta=25^\circ \times 2=50^\circ$$

=> Ans - (C)

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