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Solution
If the difference between all the pairs is same, then the pair whose first number is the greatest will be the smallest pair, and vice-versa the pair with smallest number will be largest.
Here, difference in each pair is 2, thus $$\sqrt{401}-\sqrt{399}$$ is smallest, and $$\sqrt{101}-\sqrt{99}$$ is largest.
=> Ans - (A)
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