If the perimeter of a square is 44 cm, then what is the diagonal (in cm) of the square?
Let side of square = $$s$$ cm
=> Perimeter = $$4s=44$$
=> $$s=\frac{44}{4}=11$$ cm
Thus, diagonal = $$d=\sqrt{s^2+s^2}$$
=> $$d=s\sqrt2$$
=> $$d=11\sqrt2$$ cm
=> Ans - (A)
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