Question 127

Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the some examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?

Solution

Let maximum marks in the examination be $$100x$$ and passing marks be $$y$$

Peter got 30% of the maximum marks, => $$30x+10=y$$ ----------(i)

Similarly, for Paul = $$40x-15=y$$ -------(ii)

Subtracting equation (i) from (ii), => $$10x=25$$

=> $$x=2.5$$

Substituting it in equation (ii), we get : Passing marks = $$y=85$$

=> Ans - (D)

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