Question 126

I is the incentre of $$\triangle$$ABC of $$\angle A = 46^\circ$$, then $$\angle BIC = ?$$

Solution

If I is the incentre of $$\triangle ABC then \angle BIC = 90\degree + \frac{\angle A}{2}$$

$$\angle BIC = 90\degree + \frac{46}{2} = 90 + 23 = 113\degree$$


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