A is 75% less than B and C is 75% of the difference between A and B. C is what percentage more than A?
As per the question,
Let B is = 100
So, as per the condition, A is 75% less than B, so A=25
As per the condition, c=$$\dfrac{(A-B)\times 75}{100}=\dfrac{(100-25)\times 75}{100}=\dfrac{225}{4}$$
Hence, the required percentage $$=\dfrac{\dfrac{(225}{4}-25)\times 100}{25}=\dfrac{(225-100)\times 100}{100}=125$$
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