Question 123

A boy walks from his house to the park which is 500 m away in 5 minutes and walks backs in 7 minutes. His average speed (in km/h) is:

Solution

Given,

The distance between home and park= 500 m

Average Speed=$$\frac{Total Distance Covered}{Total time taken}$$

Average Speed=$$\frac{500+500}{\frac{5}{60}+\frac{7}{60}}$$

Average Speed=5000$$ \frac{m}{\sec}$$

Average Speed=5$$ \frac{Km}{hr}$$

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